Hi there
I have a script with a function that builds a more comprehensive kind
of array for parsing arguments given a script in PHP (this is a
backup-script I'm currently working on).
My problem is in "THE PARSING OF ARGS PART" when I'm asking the array
if the key exists in the array it returns 0. The key exists, I know
because of the output from the function ( var_dump($array) ), but the
function 'in_array()' only returns true if I ask for a value.
Does anyone know if I can use anything else to give me the possibility
to also ask for the keys, or do I have to write a 'in_array()'-kind of
function myself ??
#! /local/bin/php -q
<?PHP // -*- C++ -*-
function parse_arg( $argv, $argc ) {
$array = Array();
for ( $i = 0 ; $i < $argc ; $i++ ) {
if ( ereg( "-", $argv[ $i ] ) ) {
if ( ereg( "-", $argv[ $i + 1 ] ) ) {
$array[ "$argv[$i]" ] = "";
} else {
$array[ "$argv[$i]" ] = $argv[ $i + 1 ];
$i = $i + 1;
}
}
}
var_dump ($array);
return $array;
}
// THE PARSING OF ARGS PART
$arr = parse_arg( $argv, $argc );
if ( in_array( "-h", $arr ) ) { // This doesnt work
print $usage;
exit;
} elseif ( in_array( "-b", $arr ) ) { // This doesnt work
$backup = 1;
} elseif ( in_array( "-d", $arr ) ) { // This doesnt work
while ( list ( $key, $val ) = each ( $arr ) ) {
if ( $key == "-d" ) {
if ( $val == "" ) {
print "No PATH to switch \"-d\"\nExiting\n";
exit;
} else {
$dir = $val;
if ( !is_dir( $dir ) ) {
print "This directory [$dir] doesnt exist\n";
exit;
} else {
$run = 1;
}
}
}
}
}
?>
--
Knut
------
Knut H. Hassel Nielsen
Principal Engineer / Avdelingsingeniør
Norwegian University of Science and Technology / NTNU
Department of Computer and Information Science / IDI
N-7491 Trondheim, Norway
Phone Office / Telefon jobb : (+47) 73 59 18 46
Fax Office / Telefax jobb : (+47) 73 59 17 33
Cell. Phone / Mobiltelefon : 91 59 86 06
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