Forgive me if my math is askew, but doesn't the negative imply the
number is signed? If I remember from my C++ days, a declaration of:

unsigned int blah;

Meant you could not store negative numbers in that variable. Hence,
negatives would be signed. No?


On Tue, 2004-06-08 at 12:52, René Fournier wrote:
> $dec = -333371788;
> echo $dec."\n";
> 
> $hex = dechex($dec)."\n";
> $dec2 = hexdec($hex)."\n";
> 
> echo $dec2."\n";
> 
> -= PRODUCES: =-
> 
> -333371788
> 3961595508
> 
> 
> Is this something about signed versus unsigned integers? What I really 
> would like to do is convert that negative number (-333371788), which I 
> suppose is unsigned to a signed integer (3961595508) without having to 
> convert it to hex, then back to decimal.
> 
> ....Rene
-- 

Adam Voigt
[EMAIL PROTECTED]

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