* Thus wrote I.A. Gray: > Hi all, > > When I use the $_SERVER to get a query string it doesn't ever seem to return > me anything: > > $queryy = $_SERVER['QUERY_STRING']; > > In my webstats script, 790 are blank and 2 give the value of "loc=uk" and > "currentID=6" - not very satisfactuary! > > Why is this happening? Could I get the search string from the referer web > site? It sounds like a bit of a faff, but is this what I have to do?
The referer and its query string are in: $_SERVER['REFERER'] You'll have to substr() the strpos() of ? to get the query sting. > > Say a referer website is > http://www.google.co.uk/search?q=web+design+for+performers&ie=UTF-8&hl=en&me > ta= > > is there a good way of getting the query string "web design for performers" > ? > > for Yahoo it is different: > > http://search.yahoo.com/search?p=biography+examples&ei=UTF-8&fr=fp-tab-web-t > &n=20&fl=0&x=wrt > > the search string is followed by "p=" Once you get the query string parsed out of the referer you can then use that string to pass to parse_str()... parse_str($query, $queryparts); $queryparts['q'] // the search term from google search $queryparts['p'] // the search term from yahoo search and if $queryparts['btnI'] == "I'm Feeling Lucky" make sure you keep note of that 'q' search term :) Curt -- First, let me assure you that this is not one of those shady pyramid schemes you've been hearing about. No, sir. Our model is the trapezoid! -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
