Eric Boerner wrote:
Hello all,
I am having trouble setting array data from within a MySQL results query. I have modified data from the result and wish to enter it into it's own array ($data). That then is used to generate a graph. The following code basically gives me an empty array...
I doubt the array is empty. It may not contain what you think it should, though. Try using print_r() on $data as you run through the code so you can see what it contains.
if ($sig1 > "-150") { $aval = "$sig1"; }
Don't put quotes around -150. As you have it right now, you're comparing strings. If $sig1 is a number, PHP plays nice and assumes you mean -150 instead of "-150", though. Also, you don't need quotes around $sig1 at the end of the line.
if ($sig2 > "-150") { $bval = "$sig2"; } if ($bval > $aval)
{$aval = bval;}
Missing a dollar sign for "bval" on this line, unless "bval" is really a constant. Same deal with the quotes, too.
if ($sig3 > "-150") { $bval = "$sig3"; } if ($bval > $aval)
{$aval = $bval;}
Same deal here with the quotes, also.
$data[] = array('$time' => '$time','$aval' => 'aval');
Variables in single quotes are not evaluated. '$val' is not the same as "$val". Either way, you don't need any quotes here (assuming you mean $aval for the last entry.
$data[] = array($time=>$time, $aval=>$aval);
$aval = "-999";
$aval = -999;
Again, $data has something in it so long as your query is running. It is probably just not what you think it is.
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