Hello.

Cannot find any unexpected dollar-sign ($) in this code.
But please enclose the associative array-indexes within quotation-marks and run your script again.


[code]
$foo = $_POST['assoc_index'];
[/code]


Daniel

Harlequin wrote:
I've checked my syntax but obviously missing something.

Would anyone mind a quick scan:

// Convert Values to Variables:
  $Title = $_POST[Title];
  $ChristianName = $_POST[ChristianName];
  $MiddleName = $_POST[MiddleName];
  $Surname = $_POST[Surname];
  $HomePhone = $_POST[HomePhone];
  $Address01 = $_POST[Address01];
  $Address02 = $_POST[Address02];
  $Address03 = $_POST[Address03];
  $City = $_POST[City];
  $Postcode = $_POST[Postcode];
  $Country = $_POST[Country];
  $Nationality = $_POST[Nationality];
  $Gender = $_POST[Gender];
  $WorkPermitRequired = $_POST[WorkPermitRequired];
  $MyStatus = $_POST[MyStatus];

// Dump Data Into MembersData:
  $UserDataDump = "INSERT INTO MembersData (Title, ChristianName,
MiddleName, Surname, DOB, TelephoneHome, Address01, Address02, Address03,
AddressCity, AddressPostcode, AddressCountry, Nationality, Gender,
WorkPermit, Status)

VALUES('$Title','$ChristianName','$MiddleName','$Surname','$HomePhone','$Add
ress01','$Address02','$Address03','$City','$Postcode','$Country','$Nationali
ty','$Gender','$WorkPermitRequired','$MyStatus')";
   mysql_query($UserDataDump) or die("Couldn't Create User Data Entry. MySQL
Error: " . mysql_error());



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