On Sat, 24 Jul 2004 12:09:41 -0400, Scot L. Harris wrote:
On Sat, 2004-07-24 at 12:05, Robb Kerr wrote:
What's wrong with this syntax. I just can't see my mistake.
if ($vBkgrndImage == "AnswerPage") { if ($vAnswerID_RS_PageContent != $row_RS_PageContent['CorrectAnswer']) { $vBkgrndImage = "Bkgrnd-Body-Incorrect.jpg"; } else { $vBkgrndImage = "Bkgrnd-Body-Correct.jpg"; } }
Thanx
Single quotes around CorrectAnswer?
What is the error you are getting?
Guessing that if it passes the syntax checks I expect your problem is it is always evaluating to one of the options and not the other.
You've got it. Syntax passes checking - always returns.. $vBkgrndImage = "Bkgrnd-Body-Correct.jpg"
Single quotes around 'CorectAnswer' is because that entry is in the style of table_recordset['field']. How else should this be coded?
Thanx
I think all column names are returned lowercased, so use $row_RS_PageContent['correctanswer']
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