beware of dates before 1969.
Justin French <[EMAIL PROTECTED]> wrote:
>
> Jason,
>
> This seems to work fine for me:
>
> <?
> $daysToAdd = 5;
> $secondsToAdd = $daysToAdd * 86400;
> $dateIn = "2004-07-24";
> $dateInStamp = strtotime($dateIn);
> echo date('m/d/Y h:i:s',$dateInStamp+$secondsToAdd);
> ?>
>
> ... as does the more condensed version:
>
> <? echo date('m/d/Y h:i:s',strtotime("2004-07-24")+(5*86400)); ?>
>
> If strtotime() is returning -1, that means that it's having trouble
> converting your YYYY-MM-DD date to a timestamp. The common pitfall is
> that you've got the month and day mixed up (YYYY-DD-MM), or that you're
> not using 2 digit numbers on the day and month (and 4 digit on the
> year).
>
> If you're having trouble with strtotime(), ech out the date you're
> trying to convert, to make sure it's what you're expecting.
>
>
> It's also worth pointing out that we've made no considerations for
> timezones, daylight savings, etc.
>
> UNIX timestamps are all GMT, so if the times you're seeing are not as
> expected (and the dates you're collecting aren't GMT dates, then you'll
> need to dig a lot deeper -- it's depends how much accuracy you want.
>
> Justin French
>
> On 07/09/2004, at 1:59 PM, Jason FB wrote:
>
> > Can anyone tell me how to convert a date stored in the format
> > "YYYY-MM-DD" to an integer of seconds since unix epoc,
> >
> > then add $daysToAdd days to this value (I suppose if the integer was a
> > number of seconds it would have to be $daysToAdd*60*60*24 to get the
> > number of seconds to add)
> >
> > then convert the new value to a timestamp which I can output using the
> > function
> >
> > string date ( string format [, int timestamp])
> >
> > I tried doing this with mktime() and couple different ways using
> > strtotime() and also with strftime() but I kept getting -1 as the
> > result for strtotime() indicating the function couldn't interpret the
> > given date.
> >
> > I've been through all the date-related functions in the manual I can
> > think of, but I'm stumpped on this one...
>
> ---
> Justin French
> http://indent.com.au
>
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