[PHP] readdir behavior I cannot understand

[Jason FB]

PHP General List,
I am trying to read the contents of a directory on a server and 
perform imagemagick operations on each JPG found inside the 
directory. The area where I am stuck currently is not the image 
manipulation but the PHP function readdir().

Can anyone explain why I am having this behavior with PHP using the 
scripts out of the manual pages for readdir()

Hereis my script, I copied and pasted Example 1 from this page:
http://us4.php.net/manual/en/function.readdir.php
You will see that the only way that I changed I initialize two 
variables at the very top that set the directory of the directory to 
open. The script should read the contents of the directory and print 
them to the resulting page.

Instead, it returns a the following parse error
Parse error: parse error, unexpected T_CONSTANT_ENCAPSED_STRING in 
/Users/jason/Sites/images_exotic/REDESIGN2 FALL 
04/admin/check_set_local.php on line 4

I see this PHP behavior on both Windows Server running PHP 4.3.2 and 
on my own Mac (OS X client) running apache as a "Personal Web 
Sharing" PHP version 4.3.6

Any help is appreciated.  The contents of the script which I cannot 
get the parse error out of is below.

On this vein, can anyone tell me a succinct explanation of the 
bang-equal-equal (!==) operator in contrast to the bang-equal (!=) 
operator?

I've never seen that before, is it borrowed from other languages? I 
do not remember it from when I was learning C++.

Thanks.
-JFB-

<?php
// Note that !== did not exist until 4.0.0-RC2
$root_dir = "/Users/jason/Sites/";
$folder_on_server "test";
if ($handle = opendir($root_dir . $folder_on_server)) {
    echo "Directory handle: $handle\n";
    echo "Files:\n";
     /* This is the correct way to loop over the directory. */
     while (false !== ($file = readdir($handle))) {
        echo "$file\n";
    }
     closedir($handle);
 }
?>