It still doesn't work :(... When I try to destroy the session without asking
if there's a session_id, it gives me a warning, I fixed it with the
if(session_id()) but still, when the user logs in again with a different
profile, in the same browser window, the profile that is loaded is the
previous one...
Here I copy the logout.php code:
<?
$_SESSION['validlogin']="";
$_SESSION['username']="";
$_SESSION['password']=""; //destroy the sessions array
$_SESSION = array();
//destroy the session
if(session_id()){
session_destroy();
}
?>
And the code that runs when the user logs in:
<?
$username=trim($_POST['user']);
$password=trim($_POST['pwd']);
if(session_id()){echo('Error, please contact tech support'); exit();}
if(validateuser()){
session_start();
$_SESSION['validlogin']=true;
$_SESSION['username']=$username;
$_SESSION['password']=$password;
}
...
?>
Any ideas why the session variables get set to their first value after
starting the session for the second time? Should I create a different
session id each time?
Tia, Lizet
-----Original Message-----
From: Reinhart Viane [mailto:[EMAIL PROTECTED]
Sent: Tuesday, October 26, 2004 12:49 PM
To: 'Lizet Pe�a de Sola'; [EMAIL PROTECTED]
Subject: RE: [PHP] @session_start generates a new session_id
Instead of:
<? $_SESSION['validlogin']=""; $_SESSION['username']="";
$_SESSION['password']=""; unset($_SESSION['validlogin']);
unset($_SESSION['username']); unset($_SESSION['password']);
session_unset(); print("username=".$_SESSION ['username']);
print("password=".$_SESSION['password']);
if(session_id()){
session_destroy();}
?>
Try this:
//unregister the sessions
$_SESSION['validlogin']=""; $_SESSION['username']="";
$_SESSION['password']=""; //destroy the sessions array $_SESSION = array();
//destroy the session
session_destroy();
Greetings
Reinhart Viane
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