The comparison operator is ==. = means "assign". Try:
if ($num == 0) {
foo(bar, baz);
}
AFAIK what your code means is "assign 0 to $num and then, if that worked,
print the error message."
HTH
Jon
-----Original Message-----
From: Jeff Oien [mailto:[EMAIL PROTECTED]]
Sent: 06 April 2001 17:51
To: PHP
Subject: [PHP] PHP/MySQL Code
This code won't work. I'm trying to get an error if the username
is entered incorrectly but it won't go through the if brackets. I even
tried printing out $num and it's 0. I also tried
if ($num = "0") {
if ($num = '0') {
<?php
include("connect.php");
$result=mysql_query("select * from table where
username='$username'",$connection) or die ("Can't do it");
$num = mysql_numrows($result);
if ($num = 0) {
print "<html>error message etc.
exit;
}
Jeff Oien
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