Hi,
I am trying to add "x" days to the current date for a calendar program that I
am writing. "x" represents any integer from 1 to 7. So, for x=4, the program
will get the current date
2004-11-06
and add 4 days to it:
2004-11-10
I need it to account for the next month if I want to add 4 days to 2004-11-29,
so the result would be 2004-12-03, not 2004-11-33. It would need the same
functionality in moving the year to 2005-01-02 when I add 3 days to 2004-12-30.
I hope that I've explained my objective clearly. I have tried getting the date
using
$today = date("Y-m-d");
and then trying to add "x" to it, but it only adds "x" to the year, not the day
value. So how can I get PHP to add "x" to the day value? Any help would be
awesome! Thanks,
Matt
Matt Cassarino
206 484 4626
[EMAIL PROTECTED]
www.mattcass.com
