well $user['password'] has no double quotes around it. ----- Original Message ----- From: "Jonathan Duncan" <[EMAIL PROTECTED]> To: <[EMAIL PROTECTED]> Sent: Saturday, December 11, 2004 8:09 PM Subject: [PHP] php variables in a backtick command
> I am trying to run a shell command with backticks. However, I get a parse > error. Is it because I have an array variable in there? > > $result = `adduser -l=$dist_id -p=$user['password'] --f="$user['name_first'] > $user['name_last']"`; > > Do I need to assign the value to a regular variable before I put it in > there? Like this? > > $pword=$user['password'] > $fname =$user['name_first'] > $lname =$user['name_last'] > $result = `adduser -l=$dist_id -p=$pword --f="$fname $lname"`; > > Thanks, > Jonathan > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > > > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
