If I were any more confused my head would split open. This just plain makes
no sense, and I'm wondering if it's just a bug in PHP.
Consider the following code:
$arvar = array(&$var1, &$var2, &$var3);
function vartest(&$arvar)
{
echo '<br>', $arvar[0], $arvar[1], $arvar[2];
$arvar[1] = 'Inside2 ';
echo '<br>', $arvar[1];
}
vartest($arvar);
echo '<br>', $arvar[1];
echo '<br>', $var2;
It outputs one blank line, then:
ArrayArrayArray
n
n
Inside2
Ok, so this is kind of weird. First, how the hell did those "n"s get in
there?
But that's not the weird part. If inside the function you use var_dump() on
$arvar[0], var_dump returns NULL. If you run it on $arvar, you get NULL.
So why did $arvar[0] get echo'ed as "Array", but it is in fact NULL?
But if it's just one great big round of null, how did it change the value of
$var2?
Honestly, this is killing me here. Here is what I want to do:
Pass $val1 and $val2 by reference into an array.
Operate on the array inside of a function.
Have the changes made to the array effect $val1 and $val2.
In C I could use an array of pointers. But how in hell do I do it in PHP?
Honestly, I'm at my wit's end here and I don't have a clue what is going
on...I'll post again with some more insanely unbelievable confusing code
results if need be.
--
Plutarck
Should be working on something...
...but forgot what it was.
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