Well, in this code, you are going to receive one line from your table that
displays the total number of records. And that is it. Here is a sample from
one of my tables, using the MySQL CLI:
mysql> select count(*) from locker;
+----------+
| count(*) |
+----------+
| 47 |
+----------+
1 row in set (1.65 sec)
If you can be a little more specific about what you want, maybe type up what
you expect out, we can fix your query statement.
Also, in this line:
>> <b><?php echo $record_count ?> </b></font>
You should put a ';' after the variable, just to save yourself the hassle of
a parse error, when you get working code.
On 4/9/01 9:32 AM, "Michael O'Neal" <[EMAIL PROTECTED]> wrote:
> Hi,
>
> I'm trying to display a record count of some sort on a page I'm working
> on. For example, "Record 1 of 15". I can display the 1st number ok, but
> I'm a bit confused on what the count function should look like for the
> 2nd number (15, in this case). Here is my current (not working) code.
>
>> <?php
>>
>> $query = "SELECT count(*) FROM mango_pr";
>> $result = mysql_query($query);
>> $record_count = mysql_fetch_row($result);
>>
>>
>> ?>
>
>
> And then I'm calling the code with an "echo" later on:
>
>> <b><?php echo $record_count ?> </b></font>
>
>
> This obviously isn't right...can anyone offer any suggestions?
>
> Thanks,
>
> mto
>
>
>
> Michael O'Neal
> Web Producer/ Autocrosser
> ST 28 '89 Civic Si
> ---------------------
> M A N G O
> B O U L D E R
> ---------------------
> http://www.thinkmango.com
> [EMAIL PROTECTED]
> p-303.442.1821
> f-303.938.8507
>
>
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