Re: [PHP] if(date("Y-m-d") >

[Travis Conway]

Maybe this will help.  Just keep adding to $var[] until you add all your 
weeks.  Then execute it.  This is written to run on the command line, but 
you can replace the \n with <br> to get your breaks in HTML.

<?
       $var = Array();
       $var[] = "2005-01-02";
       $var[] = "2005-01-09";
       $var[] = "2005-01-16";
       $numweeks = count($var);
       echo "Number of weeks: " . $numweeks . "\n";
       $today = date("Y-m-d");
       for ($i=0;$i<$numweeks;$i++) {
               if ($today >= $var[$i]) {
                       $lastweek = $i + 1;
               }
       }
       echo "This is week $lastweek.\n";
?>
HTH
Trav
www.pinkbunnysuit.com
----- Original Message ----- 
From: "John Taylor-Johnston" <[EMAIL PROTECTED]>
To: <php-general@lists.php.net>
Sent: Monday, January 10, 2005 12:08 PM
Subject: [PHP] if(date("Y-m-d") >


Hi,
I would like some help to improve this script. I'm a teacher with a 
schedule of 17 weeks.
Instead of using if(date("Y-m-d") >= $week3)  I would like to do a "for i 
= 1 to 17" and if the current date date("Y-m-d") = week[i] I would like to 
echo "This is week $week[i]";

Can someone show me how please?
<?php
#old code:
$week1 = "2005-01-17";
$week2 = "2005-01-24";
...
$week17 = "2005-05-09;
if(date("Y-m-d") >= $week3)
{
echo "this is week 3");
}
?>
Thanks,
John
--
John Taylor-Johnston
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