Dmitry wrote:
Thanks,
but I think that this code more easy.

class a {
 function say() { echo "A"; }
 function run() { $this->say(); }
}
class b {
 function say() { echo "B"; }
 function run() {
    $a = new a;
    $a->run();

for starters b doesn't even extend a and secondly the b::run() method is creating an object on each invocation - not exactly good use of OO.

besides which b::run() is creating an object of an arbitrary
class, assuming b was supposed to extend a in your example above
the you have hardcoded the parent into the subclass, thats plain wrong...

my example wasn't a specific solution to your problem but an example of 3 ways to acomplish the goal of calling the version of a method in the super class. if you didn't understand something just ask.

    }
}

$obj = new b;
$obj->run();


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