Re: [PHP] assignment operator works for comparison??

[Yasuo Ohgaki]

> if($shiny = 0) This line is the same as if ((shiny = 0) == TRUE) It's common error with PHP and C. You could make use of this like if ($fp = fopen($filename,'r')) since this is the same as if (($fp = fopen($filename,'r')) == TRUE) code after this line is executed when fopen() success to open file. Regards, -- Yasuo Ohgaki ""Dan"" <[EMAIL PROTECTED]> wrote in message 9avrti$olc$[EMAIL PROTECTED]">news:9avrti$olc$[EMAIL PROTECTED]... > This confused me for awhile, because the single equal sign seemed to work > for comparison, but created inexplicable errors in my programs. It seems > strange to me that a successful variable value assignment does not return > true. > > example: > > <? > > $shiny = 1; > if($shiny = 0){ echo("This wont print"); } > echo( $shiny ); //this will return 0 > > ?> > > --Dan > > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, e-mail: [EMAIL PROTECTED] > For additional commands, e-mail: [EMAIL PROTECTED] > To contact the list administrators, e-mail: [EMAIL PROTECTED] > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]