Re: [PHP] I need to create a search that will search partial filesnames of images and display the images. Basically, I have a folder on theinternet that has security camera images dumped into it with a file namelike this:

[Vin]

"Marek Kilimajer" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
> Vin wrote:
> > I need to create a search that will search partial files names of images
and
> > display the images.  Basically, I have a folder on the internet that has
> > security camera images dumped into it with a file name like this:
> >
> > MDcameraname20050109104846001N38B.jpg
> > MDcameranameYYYYMMDDHHMMSS001N38B
> >
> > So what I would like to create is a search that will allow a user to
input
> > the year, month, day, and hour, and have the website display the images
from
> > that hour. Could someone help me with this?
> >
> > Thanks in advance,
> > Vinny
> >
>
> http://sk2.php.net/manual/en/function.glob.php


thanks, that is perfect. Now I have a follow up question if you don't mind.
How can I take $filename and break it apart to display the time/date the
picture was taken in a nice readable format?

here is my code:

<?php
$x = 0;
$count = 0;
$matches = glob("*$y$m$d$h*.JPG");
if ( is_array ( $matches ) )
 {
 foreach ( $matches as $filename)
   {
   if ($x < 4)
    {
    echo "<td>";
    echo "<a href=javascript:pop('";
    echo $filename;
    echo "');>";
    echo "<img src='";
    echo $filename;
    echo "' border=0 width=240 height=180></a>";
    $count = $count+1;
    echo "<br>";
    echo $filename;
    echo "</td>";
    $x = $x + 1;
    } else {
    echo "</tr><tr>";
    $x = 0;
    }
   }
 }

echo "<br><br>";
echo $count . " images found";
?>

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