I am not sure but maybe something like this is posible $current_year = date(Y); $qry = "SELECT * FROM `table` WHERE ($current_year-YEAR(birthday)) BETWEEN 25 AND 26"
"Matthew Weier O'Phinney" <[EMAIL PROTECTED]> wrote in message news:[EMAIL PROTECTED] >* Ryan A <[EMAIL PROTECTED]> : >> Thanks for replying. >> >> > SELECT * FROM >> > `table` >> > WHERE `age` BETWEEN 25 AND 26; >> >> I knew the above, but how do i use it with my date field when i have >> birthdates like this: >> 01-01-1969 >> and 03-05-1955 > > Just like you would in the example above -- only with dates that are > compliant with your RDBMS, and using the earliest date first. The > formats you give -- 'MM-DD-YYYY' won't work in most RDBMS'; typically > you go from most general to most specific, e.g. 'YYYY-MM-DD'. So, using > the dates you gave: > > SELECT * FROM `table` WHERE `age` BETWEEN '1955-03-05' AND > '1969-01-01'; > > The date fields may be subject to the UNIX epoch; if so, neither of the > dates above will be valid (epoch started 1970-01-01). Check the manual > for your RDBMS to see if this is the case. > > Now, based on the OP's original question, about finding all users > between an age range, one would need to determine the start date and end > date prior to passing in the SQL. This can easily be done with > strtotime(): > > $ages = explode(',', $_GET['ages'], 2); // get the start/end ages > $startDate = date("Y-m-d", strtotime("-$ages[0] years")); > $endDate = date("Y-m-d", strtotime("-$ages[1] years")); > $sql = "SELECT * FROM `table` WHERE `age` BETWEEN $startDate AND > $endDate"; > > Hope that helps. > >> On 5/8/2005 4:28:44 PM, Andy Pieters ([EMAIL PROTECTED]) wrote: >> > On Sunday 08 May 2005 15:20, Ryan A wrote: >> > > Sorry I know this is OT but I'm hoping someone will still >> > > help...it should be quite simple :-) >> > > I have a field in the database called "age" which is a DATE field. >> > > >> > > I also have a webform where the user can select between which ages >> > > he wants the records shown... >> > > eg: if he types 23,25 then I should get all results where >> > > age > =23 and age <=25 >> > > >> > SELECT * FROM >> > `table` >> > WHERE `age` BETWEEN 25 AND 26; >> > >> > You might want to sanitize your input first. >> > >> > Like using intval() on your input or mysql_escape_string > > > -- > Matthew Weier O'Phinney | WEBSITES: > Webmaster and IT Specialist | http://www.garden.org > National Gardening Association | http://www.kidsgardening.com > 802-863-5251 x156 | http://nationalgardenmonth.org > mailto:[EMAIL PROTECTED] | http://vermontbotanical.org -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
