quoth the Mark Sargent:
<snip>
> <html>
> <body>
> <h1><center>Jumbo Status</center></h1><br>
> <?php
> $db = mysql_connect("localhost", "root", "grunger");
> mysql_select_db("status",$db);
> $result = mysql_query("SELECT ProductTypes.product_type_detail FROM
> ProductTypes",$db);
> $myrow = mysql_fetch_array($result);
> $num = mysql_num_rows($result);
> ?>
> <table aligh="center" border="2">
> <tr>
> <td>Product Type</td>
> </tr>
> <?
> $i=0;
> while ($i < $num){
> $product_type=mysql_result($result,$i,"product_type_detail");
> echo "<tr><td><? echo $product_type ?></td></tr>"You are already in a php block here. Why the '<?' ? Try: echo "<tr><td>$product_type</td></tr>"; > } > $i++ As the error message is trying to tell you, php statements are terminated with semi-colons: $i++; > ?> > </table> > </body> > </html> > > I get the folowing error, > > *Parse error*: parse error, unexpected '}', expecting ',' or ';' in > */var/www/html/products.php* on line *20 > * > which is the $i++ section. > > Cheers. > > Mark Sargent. -d -- darren kirby :: Part of the problem since 1976 :: http://badcomputer.org "...the number of UNIX installations has grown to 10, with more expected..." - Dennis Ritchie and Ken Thompson, June 1972
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