This would have been easier if you'd posted the php code to create the
array, as opposed to the output of print_r. I did this:
<?php
$arr = array(
array(
'name' => 'food',
'children' => array(
array(
'name' => 'meat',
'children' =>
array(
array('name' => "beef", "children" => NULL),
array("name" => "pork", "children" => NULL)
)
),
array(
'name' => 'friut',
'children' =>
array(
array('name' => "pears", "children" => NULL),
array('name' => "apples", "children" => NULL),
array('name' => "oranges", "children" => NULL)
)
),
array(
'name' => 'veg',
'children' =>
array(
array('name' => "parsnips", "children" => NULL),
array('name' => "carrots", "children" => NULL),
array('name' => "tomatoes", "children" => NULL),
)
)
)
)
);
function display_array($arr, $prefix=""){
while(list($k, $v) = each($arr)){
if(is_array($ca = $arr[$k]['children'])){
display_array($ca, $prefix . $arr[$k]['name'] . ":");
} else {
echo $prefix . $arr[$k]['name'] . "\n";
}
}
}
display_array($arr);
?>
On 5/26/05, Chris W. Parker <[EMAIL PROTECTED]> wrote:
> Marek Kilimajer <mailto:[EMAIL PROTECTED]>
> on Thursday, May 26, 2005 11:35 AM said:
>
> > untested:
> >
> > function display($array, $prefix = '') {
> > echo $prefix ':' . $array['name'] . "\n";
> > if(is_array($array['children']) && $array['children']) {
> > foreach($array['children'] as $child) {
> > display($child, $prefix ':' . $array['name']);
> > }
> > }
> > }
>
> Thanks Marek.
>
> I've had one suggestion off list also and, although I haven't been able
> to test this myself, I think my major mistake is that I've been doing
> the foreach() BEFORE checking for the existence of an array. Whereas
> both suggestions so far are checking for the existence of an array
> before the foreach().
>
> I'll report back to the list with my results. Probably tomorrow.
>
>
> Thanks,
> Chris.
>
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