In php5 any object is moving as reference. you need special declaration, if
you want to duplicate(copy/clone) an object.
regards
david
----- Original Message -----
From: "Robert Cummings" <[EMAIL PROTECTED]>
To: "Matthew Weier O'Phinney" <[EMAIL PROTECTED]>
Cc: "PHP-General" <php-general@lists.php.net>
Sent: Thursday, June 23, 2005 11:50 PM
Subject: Re: [PHP] Re: Strange notation to create object
On Thu, 2005-06-23 at 15:28, Matthew Weier O'Phinney wrote:
* Robert Cummings <[EMAIL PROTECTED]> :
> On Thu, 2005-06-23 at 13:36, Matthew Weier O'Phinney wrote:
> > * Robert Cummings <[EMAIL PROTECTED]> :
> > > On Thu, 2005-06-23 at 11:32, Matthew Weier O'Phinney wrote:
> > > > The above notation is unnecessary when developing in PHP5, as
> > > > objects in
> > > > PHP5 are passed by reference by default. However, in PHP4, this
> > > > was
> > >
> > > Not entirely, there's still a subtle difference in PHP5 between
> > > assigning an object with = versus assigning with = &.
> >
> > Would you mind explaining the difference? I've seen nothing in the
> > docs,
> > to indicate that assigning objects with =& in PHP5 is necessary, or
> > even
> > desired. My experience with PHP5 hasn't shown this either. I'd be
> > interested to know to what you refer.
>
> See for yourself when running the following script:
>
> <?php
>
> class a
> {
> }
>
> class b
> {
> }
>
> $aObj = new a();
> $bObj = new b();
>
> $foo1 = $aObj;
> $foo2 = $aObj;
> $foo3 = $foo1;
> $foo4 = &$foo2;
>
> echo "------------------\n";
> print_r( $foo1 );
> print_r( $foo2 );
> print_r( $foo3 );
> print_r( $foo4 );
>
> $foo1 = $bObj;
> $foo2 = $bObj;
>
> echo "------------------\n";
> print_r( $foo1 );
> print_r( $foo2 );
> print_r( $foo3 );
> print_r( $foo4 );
>
> $foo1 = &$aObj;
> ?>
This doesn't demonstrate what the OP was talking about, which is initial
assignment of an object using a reference operator. The results of this
make perfect sense to me -- the references are passed exactly as I would
expect.
Let me rephrase my question to you: is there a reason to do the initial
object assignment using a reference operator using PHP5? I.e., is there
a good reason to do this:
$foo =& new Foo();
instead of:
$foo = new Foo();
I haven't seen any reason to do the former case using PHP5.
Your original response said that the above notation was unneccessary, I
took that to mean the & operator for reference. Looking back I see ow
that your comment was ambiguous, and I agree there is no need for the &
when assigning a new object. I was merely clarifying that references and
normal assignment are not synonymous for objects in PHP 5.
Cheers,
Rob.
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