Yes, you're right. It's false
This dont't work too.
foreach ($dbh->query('SELECT * FROM words') as $row) {
echo $row['word'] . "<br>";
}
But this works
$stmt = $dbh->prepare('select * from words');
$stmt->execute();
$rows = $stmt->fetchAll();
echo count($rows) . "<br><br>";
"Marek Kilimajer" <[EMAIL PROTECTED]> escreveu na mensagem
news:[EMAIL PROTECTED]
> Holografix wrote:
>> print_r($stmt) prints nothing. print($stmt) print nothing too.
>>
>> I checked errorCode() and it prints 0000.
>
> Then it seems $stmt is false. var_dump() is more verbose about it.
>
>>
>>
>> "Marek Kilimajer" <[EMAIL PROTECTED]> escreveu na mensagem
>> news:[EMAIL PROTECTED]
>>
>>>Holografix wrote:
>>>
>>>>Hi Marek
>>>>
>>>>It's print_r($row), not print_r($stmt) ;)
>>>
>>>That's what I'm asking - If you put print_r($stmt) in that line, what
>>>does it print?
>>>
>>>
>>>>
>>>>
>>>>"Marek Kilimajer" <[EMAIL PROTECTED]> escreveu na mensagem
>>>>news:[EMAIL PROTECTED]
>>>>
>>>>
>>>>>Holografix wrote:
>>>>>
>>>>>
>>>>>>Hi. When using this example from
>>>>>>http://netevil.org/talks/index.php?t=pdo&s=20, the site of pdo's
>>>>>>author I have this error:
>>>>>>
>>>>>>Fatal error: Call to a member function fetchAll() on a non-object in
>>>>>>/www/home/testes/pdo_my1.php on line 17
>>>>>>
>>>>>>
>>>>>>$dbh = new PDO('mysql:host=localhost;dbname=dbtest', 'user', 'pass');
>>>>>>$stmt = $dbh->query("SELECT * FROM foo");
>>>>>
>>>>>what does print_r($stmt); print here?
>>>>>
>>>>>
>>>>>
>>>>>>$rows = $stmt->fetchAll();
>>>>>>$count = count($rows);
>>>>>>foreach ($rows as $row) {
>>>>>> print_r($row);
>>>>>>}
>>>>>>$stmt = null;
>>>>>>
>>>>>>Wht's wrong with the example?
>>>>>>
>>>>>>Greetings
>>>>>>holografix
>>>>>>
>>>>
>>
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