Hi, You can use your code1.php as
<?php return rand(1,10000); ?> and then you can get the value as $returnedData = require("code1.php"); On 9/14/05, Gustav Wiberg <[EMAIL PROTECTED]> wrote: > > Hi there! > > Look at the following code > > > code1.php > > <?php > echo rand(1,10000); > ?> > > > code2.php > > //Here I want to get the output of code1.php without using functions. Is > it > possible? > // > //Something like $test = require("http://<domain>/mobil_info.php"); but > instead of returning 1 at success I want to return the random value... > > Why? Because I want to be platform independent. I'm connecting to a server > running PHP 4.3.11. > > Ideas? Please give me! > > /G > http://www.varupiraten.se > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > > -- *** phpgurru.com <http://phpgurru.com> [A php resource provider] *** \\\|/// \\ - - // ( @ @ ) PHP is too logical for my brain +---oOOo-(_)-oOOo------------------------------------------+ | Mian Shafiq ur Rehman | phpgurru.com <http://phpgurru.com> [A php resource provider] | 107 B, New Town, Multan Road | Lahore Pakistan | | Mobile: 0300 423 9385 | | ooo0 http://www.phpgurru.com | ( ) 0ooo E-Mail: [EMAIL PROTECTED] +---\ (----( )------------------------------------------+ \_) ) / (_/