Re: [PHP] Problem with Regexp

[Yannick Mortier]

Richard Heyes schrieb:

Yannick Mortier wrote:
Hello,

I have the string:

<tr><td><img src="http://www.runescape.com/img/hiscores/attack.gif"; 
valign="bottom" width=16 height=16 /></td><td>&nbsp;</td><td><a 
href="hiscoreuser.cgi?username=zezima&category=1" 
class=c>Attack</a></td><td align="right">4</td><td 
align="right">99</td><td align="right">53,156,556</td></tr>


and I apply preg_match_all:

preg_match_all("/(<tr><td><img 
src=\"http:\/\/www.runescape.com\/img\/hiscores\/attack.gif\" 
valign=\"bottom\" width=16 height=16 \/><\/td><td>&nbsp;<\/td><td><a 
href=\"hiscoreuser.cgi\?username=)([\w])+(&category=1\" 
class=c>Attack<\/a><\/td><td align=\"right\">)([1-9])+(<\/td><td 
align=\"right\">)([1-9])+(<\/td><td 
align=\"right\">)([1-9,])+(<\/td><\/tr>)/",$seite,$attack);


...

But I would expect to get
[2] => Array
       (
           [0] => zezima
       )
[6] => Array
       (
           [0] => 99
       )
[8] => Array
       (
           [0] => 53,156,556        )

Instead of the values above.

Can you explain me how I can get those values?


Try something like:

preg_match_all('#username=([^&]+).+<td align="right">\d+</td><td 
align="right">(\d+)</td><td align="right">([\d, ]+)</td>#i', $seite, 
$matches);

print_r($matches);

Not tested - might need tweaking.

Now it works! I still use mine, but i put the + directly after the 
closing bracket:
([\d]+) instead of ([\d])+

Thanks a lot for your help! I looked at your reg exp and saw this.

Yannick Mortier

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