I do not know if it is more efficient, but you can do this:
$year = date("Y");
$Query = sprintf("SELECT y_id, year FROM Year WHERE year <= %s ORDER BY year
DESC;", $year);
$Result = mysql_query($Query);
May I ask you what you are using this table for?
/Peter
-----Original Message-----
From: Paul Goepfert [mailto:[EMAIL PROTECTED]
Sent: Tuesday, February 07, 2006 7:55 AM
To: [email protected]
Subject: [PHP] Is this the most effient to do with php an mysql?
Hi all,
I have a table of years going from 1985 - 2008. These years represent
the purchase year. I have created a SQL statement that selects the
years that are available for purchase years. For example 2006 -1985.
Here is the SQL statement I created to produce that output.
SELECT y_id, year FROM Year WHERE year <= extract(year from now())
ORDER BY year desc;
Is there a more efficient way to do this using more PHP and less mysql?
Thanks
Paul
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php