Use double quotes/ On 07/04/06, David Clough <[EMAIL PROTECTED]> wrote: > > I've been bashing my head against the wall on this, and would be glad of > help to stop. > > I have a variable containing a string that contains the names of > variables, and want to output the variable with the variables it > contains evaluated. E.g. > > $foo contains 'cat' > $bar contains 'Hello $foo' > > and I want to output $bar as > > Hello cat > > The problem is that if I use > > echo $bar > > I just get > > Hello $foo > > Note that $bar is loaded from a database query, so I can't control its > contents: I just have to parse it. > > Any help appreciated. > > David. > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > >
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