for ($i = 1; $i <= 20; $i++){
if (isset($_POST[$i])){
//insert blah blah blah
}
}
Also, I don't think '1' is valid NAME for HTML specification.
You could use:
NAME="menu[1]"
Then in PHP:
$menu = $_POST['menu'];
for ($i = 1; $i <= 20; $i++){
if (isset($menu[$i])){
}
}
And, of course, you need to scrub your data.
http://phpsec.org
On Wed, May 10, 2006 3:49 am, Chris Grigor wrote:
> morning all,
>
> Is there an easier way of doing the following??
>
> form1 submitting to form1.php
> <input type="checkbox" name="1">
> <input type="checkbox" name="2">
> <input type="submit>
>
> form1.php
>
> <?php
>
> $link = mysql_connect('host', 'user', 'pass') or die ("Connection
> failed:" . mysql_error());
>
> mysql_select_db('yourdbname', $link) or die ("selection failed: " .
> mysql_error());
>
> if(isset($_POST[1])) {
> mysql_query("INSERT INTO menu (label) VALUES ('item 1
> selected')");
> }
> else {
> mysql_query("INSERT INTO menu (label) VALUES ('item 1 not
> selected')");
> }
> if(isset($_POST[2])) {
> mysql_query("INSERT INTO menu (label) VALUES ('item 2
> selected')");
> }
> else {
> mysql_query("INSERT INTO menu (label) VALUES ('item 2 not
> selected')");
> }
>
> mysql_close($link);
> ?>
>
> So my question is, if I have a form with 20 + items which can be
> checkboxes, when submitted do I need to go through each one and add it
> to the datasbase or maybe some kind of loop?.
>
> Thank you
>
> Chris
>
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