On Tue, August 15, 2006 9:19 am, Brad Bonkoski wrote: > Had this problem in the past, and always programmed around it, but > wondering if there is an easier way. > > Good Example: > Creating a setup for connecting to a mysql database. Want to do > something simple to make sure they have entered a valid > username/password for the database. > So, the idea is something like: > $rc = exec("mysql -u $user -p{$pass}", $output); > The problem is one error, the stderr does not go to the output array, > but rather to the screen. > > Previously I would redirect the stderr to a file, and then evaluate > the > contents of the file, but is there an easier way to get this into the > PHP variable with no risk of having the output make it through to the > screen?
In some OSes, in some shells, you can use: mysql -u $user -p{$pass} 2>&1 The 2>&1 is special code for "redirect stdrrr (aka 2) to stdout (aka 2)" Unless it's 2&>1 which I always forget which is which... -- Like Music? http://l-i-e.com/artists.htm -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php