Dave M G wrote:
PHP list.
This is another regular expression type of question.
The very handy PHP function trim() takes excess white space off the
beginning and end of a string.
I'd like to be able to do the same thing, except instead of white
spaces, trim excess slashes: /
So for example, all of these:
/this/that/
/this/that
this/that/
////////this/that////////////
... become:
this/that
There is also the chance of more than one slash occurring inside the
desired text:
/this/that/this/that/
So that would also need to be accounted for. The above example should
become:
this/that/this/that
I think I need to use preg_replace() for this, but, as ever, regular
expressions completely throw me.
If I'm not mistaken, "#^/*#" should get me the first slash of the
string, and more if there are more. And "#*/$#" should get me the last
slash of the string, and more if there are more.
Can I test for the first and last slash in the same expression?
I think I either need something between the two that says "ignore what's
in the middle", or and and/or statement to say "replace if this occurs
at the end, or at the beginning, or both".
I've looked around and can't seem to find a way of connecting these in
the same search. However, I'm sure that is because I'm not familiar
enough with regular expressions to know what I'm looking at.
How would I connect "#^/*#" and "#*/$#" into one regular expression?
Thank you for your time and advice.
--
Dave M G
Ubuntu 6.06 LTS
Kernel 2.6.17.7
Pentium D Dual Core Processor
PHP 5, MySQL 5, Apache 2
something like
$trimmed = preg_replace('#^/*(.+)/*$#m', '$1', $string)
should work
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