This is what I am trying to do, and for the most part it works, but it also
may be causing some of my other problems.
If $event contains invalid characters, I am returning a string that says
"Invalid Characters" So $result now contains the value 'Invalid Characters'.
Then $formerror['event'] = $result - is self explanatory.
If there are no errors nothing is returned and $result should contain
anything. But this doesn't always seem to be the case. This is one of the
problems I am having.
This is the code in a nutshell.
if($result = ValidateString($event)) { $formerror['event'] = $result;
function ValidateString($string) {
if(!preg_match("/^[-A-Za-z0-9_.' ]+$/", $string)) {
return "Invalid Characters";
}
Thanks
> -----Original Message-----
> From: Jim Lucas [mailto:[EMAIL PROTECTED]
> Sent: January 17, 2007 4:36 PM
> To: Jay Blanchard
> Cc: Beauford; PHP
> Subject: Re: [PHP] One last try at this!
>
> Jay Blanchard wrote:
> > [snip]
> >
> >> The second condition of each if statement does not contain
> equality
> >> checking, it sets the $result to ValidateString($event, "2"). That
> >> should be if($result == ValidateString($event, "2")) or if($result
> >> === ValidateString($event, "2"))
> >>
> >>
> >>
> > What if the intension was to fail if the result of ValidateString()
> > was false??
> >
> > Then it should be writen as such.
> >
> > if ( ( $result = ValidateString($event, "2") ) !== FALSE ) {
> > $formerror['event'] = $result;
> > }
> > [/snip]
> >
> > Hmmm.....did you test that?
> > $result = ValidateString($event, "2") is always TRUE,
> $result has had
> > something assigned to it unless the function ValidateString
> returns a
> > FALSE. The OP never provided the code for the function so we just
> > don't know. Also, the OP forgot to run subsequent conditions in an
> > elseif check, instead he used 3 if statements that will be
> executed each time.
> >
> >
> At one point he mentioned changing ValidateString() to return
> false on an error.
>
> At least that is what I thought he said.
>
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