Thanks everyone! A lot of great solutions!
On 2/2/07, chetan rane <[EMAIL PROTECTED]> wrote:
HI Dan
try this this should work 100%;
echo "<select>";
for ($y=0;$y<=10;$y++) {
$years=date('Y')+$y;
$short_years=date('y')+$y;
printf("<option value=\"%02d\">%d</option>",$short_years,$years);
}
echo "</select>";
On 2/2/07, Dan Shirah <[EMAIL PROTECTED]> wrote:
>
> Hello all,
>
> I am trying to populate a dropdown list to contain the current year to
10
> years in the future. Below is the code I'm using:
>
> <?PHP
> for ($y=0;$y<=10;$y++) {
> $years=date <http://php.net/date>('Y')+$y;
> $short_years=date <http://php.net/date>('y')+$y;
> echo "$short_years";
> echo "<option value=\"$short_years\">$years</option>";
> }
> ?>
> I want the selection value to be 2007, 2008, 2009, 2010.... and the
> $years
> accomplishes this. Howeverm I want the option value to be the two digit
> year ex. 07, 08, 09, 10...the $short_years semi accomplishes
> this....instead
> of getting 07, 08, 08, 10 I get 7, 8, 9, 10...how can I get it to output
> the
> two year for 07, 08, 09 without it cutting off the zero?
>
> Reagrds,
>
> Dan
>
--
Have A plesant Day
Chetan. D. Rane
Location: Pune , India
Contact: +91-9890792762
otherID: [EMAIL PROTECTED]
[EMAIL PROTECTED]
