Hello again,
I make a mistake in the image.php code at echo($row['resim']);
line. if you change this line echo($row['picture']) , your problem will be
fixed. :))))
I have written table field in Turkish. in Turkish picture means that resim
:)))))
--
Haydar TUNA
Republic Of Turkey - Ministry of National Education
Education Technology Department Ankara / TURKEY
Web: http://www.haydartuna.net
"Chris Carter" <[EMAIL PROTECTED]>, haber iletisinde sunlari
yazdi:[EMAIL PROTECTED]
>
> I have a field in database called "logos" which has one value
> "images/logos/some_logo.jpg"
>
> In my php I am trying to call it in my php file as image. With this code.
>
> $sno = $_REQUEST['sno'];
>
> $query="SELECT logos FROM table WHERE sno = '$sno'";
>
> $result=mysql_query($query);
> $num=mysql_numrows($result);
>
> mysql_close();
> $logos=mysql_result($result,$i,"logos");
>
> echo "
> <div>
> <p> $logos </p>
> </div>";
>
> ?></div>
>
> But getting errors. What is the way to call image in php file from the
> database. I know that this is a very basic question but first time for me.
> I
> ignored this in the begining but now its right infront of me.
>
> Please advice.
>
> --
> View this message in context:
> http://www.nabble.com/How-to-call-image-from-mySql-to-php-file-tf3267012.html#a9081704
> Sent from the PHP - General mailing list archive at Nabble.com.
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