> -----Original Message----- > From: Richard Lynch [mailto:[EMAIL PROTECTED] > Sent: Friday, March 02, 2007 12:35 AM > To: [EMAIL PROTECTED] > Cc: Roman Neuhauser; 'PHP Mailing' > Subject: Re: [PHP] exec from process (deamon) without shell > > On Thu, March 1, 2007 12:56 pm, [EMAIL PROTECTED] wrote: > > I tried with /bin/ls but still same thing. I just found out that the > > exitcode is -1 but the $stdout actually gives correct answer. But that > > doesn't make sense. How can I then control what action to take > > depending on the exitcode? > > I *think* this could be the result of trying to ls a bunch of files, > some of which you don't have permission to 'ls', so you are getting a > partial list of stuff, but also an error code for trying to ls stuff > you shouldn't have been doing that too, if you see what I mean... > > I am hoping that your real script is a bit more complicated, as you > currently have a shell script that runs PHP only to run a shell script > that just does 'ls', which, really, you could probably just splat into > your shell script without PHP being involved... >
[Peter Lauri - DWS Asia] It is a much more complicated logic, so therefore I am not using a shell script. I will examine how perl acts on executing the same commands and if that is catching 0 as error code I might move to run perl instead. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
