On Sun, April 22, 2007 1:05 am, John Taylor-Johnston wrote:
> $mydata->timestamp = "20070419162123";
>
> echo date('Y-m-d', $mydata->timestamp);
>
>
> result: 2038-01-18
>
> ?? What is wrong?? Should be 2007-04-19?date() takes a Unix timestamp as its input. Unix timestamps are measured as number of seconds from Jan 1, 1970, midnight, GMT, the birth of Disco. [that last was a joke...] You are handing it a pre-formatted date-stamp in YYYYMMDDHHIISS format... You could do something like: $t = '20070419162123'; $year = substr($t, 0, 4); $month = substr($t, 4, 2); $day = substr($t, 6, 2); $hour = substr($t, 8, 2); $minutes = substr($t, 10, 2); $seconds = substr($t, 12, 2); echo date(mktime($month, $day, $year, $hour, $minutes, $seconds)); I suspect strtotime() *might* handle your input and give you a Unix timestamp... I also suspect whatever you needed a Unix timestamp for in the first place could have been achieved easier before you got painted into this corner... -- Some people have a "gift" link here. Know what I want? I want you to buy a CD from some indie artist. http://cdbaby.com/browse/from/lynch Yeah, I get a buck. So? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
