On Tue, 2007-06-05 at 09:33 -0700, Jim Lucas wrote:
> Robert Cummings wrote:
> > On Tue, 2007-06-05 at 17:16 +0100, blueboy wrote:
> >> if I have an array of  3  images
> >>
> >> <table class="signup_table">
> >> <tr>
> >> <td> 1.</td>
> >> <td><input name="userfile[]" type="file"></td>
> >> </tr>
> >> <tr>
> >> <td> 2.</td>
> >> <td><input name="userfile[]" type="file"></td>
> >> </tr>
> >> <tr>
> >> <td>3.</td>
> >> <td><input name="userfile[]" type="file">
> >> </td>
> >> </tr>
> >> </table
> >>
> >> How do I access the filename? Like this?
> >>
> >> echo $fileName1 = $_FILES['userfile']['name'][0];
> >> echo $fileName2 = $_FILES['userfile']['name'][1];
> >> echo $fileName3 = $_FILES['userfile']['name'][2];
> > 
> > No, like this:
> > 
> >     echo $fileName1 = $_FILES['userfile'][1]['name'];
> >     echo $fileName2 = $_FILES['userfile'][2]['name'];
> >     echo $fileName3 = $_FILES['userfile'][3]['name'];
> > 
> > Cheers,
> > Rob.
> I suggest to the op that they use print_r() on $_FILES and all will be 
> revealed

You mean:

echo "<pre>\n";
print_r( $_FILES );
echo "\n</pre>\n";

:)

Cheers,
Rob.
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