[PHP] outputing image part 2

[Ross]

I have manually put in the url my display_image.php page to debug as
sugested and all I get is the URL of the display_image.php page output on
the screen.

This is what I see
http://xxxxxxxxxxxxxxx.co.uk/common/display_image.php


this is the display_image.php file:

$img_url="http://www.xxxxxxxxxxxxx.co.uk/images/ENapt63377/4.jpg";;

$image = imagecreatefromjpeg($img_url);
if ($image === false) { exit; }

// Get original width and height
echo $width = imagesx($image);
echo $height = imagesy($image);

// New width and height
$new_width = 200;
$new_height = 150;

// Resample
$image_resized = imagecreatetruecolor($new_width, $new_height);
imagecopyresampled($image_resized, $image, 0, 0, 0, 0, $new_width,
$new_height, $width, $height);

// Display resized image

header('Content-type: image/jpeg');
imagejpeg($image_resized);
exit();

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