You might also want to remove the comma after "url = '$url'" and try an echo
mysql_error($link) to see what the problem is.
Julian
on 5/14/01 5:46 PM, Peter Houchin - SunRentals Australia at
[EMAIL PROTECTED] wrote:
> change it to
>
> $sql = "UPDATE CLASS_ADS
> SET client_id = '$client_id', date = '$date', category = '$category',
> title = '$title', description = '$description', contact_name =
> '$contact_name, contact_number = '$contact_number', email =
> '$email', url = '$url', WHERE client_id = '$client_id' ";
>
> also if a MySQL query doesn't work I always try it on the command line :)
>
>
> Peter Houchin
> [EMAIL PROTECTED]
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>
> -----Original Message-----
> From: Laurie Landry [mailto:[EMAIL PROTECTED]]
> Sent: Tuesday, May 15, 2001 9:23 AM
> To: [EMAIL PROTECTED]
> Subject: [PHP] MySQL Query not working?
>
>
> Hi, I've got this sql setup where
>
> $sql = "UPDATE CLASS_ADS
> SET client_id = \"$client_id\", date = \"$date\", category = \"$category\",
> title = \"$title\", description = \"$description\", contact_name =
> \"$contact_name\", contact_number = \"$contact_number\", email =
> \"$email\", url = \"$url\", WHERE client_id = \"$client_id\" ";
>
> and of course the following:
>
> $sql_result = mysql_query($sql)
> or die("Couldn't execute query.");
>
> which when I test the page, it tells me it couldn't execute the query.
>
> I hope the information above is enough for someone to help me pinpoint where
> I went wrong.
>
> (all the fields in the named table in the database is set accordingly with
> one thing: the client id number is autogenerated by the database, so I'm not
> sure if the client_id should be there.)
>
> Thanks in advance:
>
> Laurie M. Landry
> <lmlweb> Design & Development
>
> www.lmlweb.com
> [EMAIL PROTECTED]
>
> T: (604) 872-6915
> F: (425) 732-1547
>
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