Sanjeev is right. You're thinking about the problem backwards. You're
trying to build a Switch inside a loop. Remember, if you ever have to do
some operating multiple times you're using a forloop, then the thing that
you want to repeat(switch case) is INSIDE the for loop.
- Dan
""Sanjeev N"" <[EMAIL PROTECTED]> wrote in message
news:[EMAIL PROTECTED]
This will not work at all..
Instead of switch try with if condition as follows
for ($i=0; $i <21; $i++) {
if(faq$i == $q){
echo $faq1;
break;
}
}
Now it works..
You can write the code to display the result how you want.. but you cant
write the code to write a code :)
Cheers
Warm Regards,
Sanjeev
http://www.sanchanworld.com
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-----Original Message-----
From: Hulf [mailto:[EMAIL PROTECTED]
Sent: Thursday, August 16, 2007 3:11 PM
To: php-general@lists.php.net
Subject: [PHP] for loop inside a switch
Hi,
switch ($q) {
for ($i=0; $i <21; $i++) {
case 'faq$i':
echo $faq1;
break;
}
}
I just want to loop out a big long list of cases.
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