On Jan 8, 2008, at 1:29 PM, Stephen Johnson wrote:
From: Jason Pruim <[EMAIL PROTECTED]>
Date: Tue, 8 Jan 2008 13:18:40 -0500
To: Jack Mays <[EMAIL PROTECTED]>
Cc: php-general General List <php-general@lists.php.net>
Subject: Re: [PHP] New years resolution: To get serious with my
programming!
Anyone wanna help? :)
Actually, the problem isn't the query... the query works fine. What I
want is for if it doesn't work, I want it to tell the user that it
didn't work.
Right now I'm just blindly accepting that the insert succeeded, and I
want to get away from that! :)
Does that explain it a little better?
If you are simply wanting to do a check on whether the insert was
successful
or not, then grab the id form the insert and check to see if it is
there...
$success = mysql_insert_id();
If(!$success){
echo "no joy.. Insert failed.";
}
Because mysql_insert_id() acts on the last performed query, be sure
to call
mysql_insert_id() immediately after the query that generates the
value.
I wasn't able to make it work with mysqli_insert_id() but you did give
me the idea of using mysqli_stmt_error() instead. Which doesn't return
anything if it was successful... So a simple:
$check = mysqli_stmt_error();
if($check = "")
redirect;
}
else
{
exit();
}
works great! Thanks for your help!
--
Jason Pruim
Raoset Inc.
Technology Manager
MQC Specialist
3251 132nd ave
Holland, MI, 49424
www.raoset.com
[EMAIL PROTECTED]
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