You're using single quotes (') and therefore variables within will not be
resolved.
try either:
exec("su - vpopmail -c
\"/var/qmail/bin/maildirmake/home/vpopmail/domains/wwlib.lan/\" .
$username");
exec('su - vpopmail -c
"/var/qmail/bin/maildirmake/home/vpopmail/domains/wwlib.lan/"' .
$username');
try echoing the result before exec'ing:
echo('su - vpopmail -c
"/var/qmail/bin/maildirmake/home/vpopmail/domains/wwlib.lan/" . $username');
cheers,
Thiago Henrique Pojda
Desenvolvimento Web
+55 41 3033-7676
[EMAIL PROTECTED]
Excelência em Softwares Financeiros
-----Mensagem original-----
De: Mário Gamito [mailto:[EMAIL PROTECTED]
Enviada em: quarta-feira, 20 de fevereiro de 2008 11:32
Para: PHP General list
Assunto: [PHP] Help on running external command
Hi,
I need to run an eternal command from a PHP page.
My code is:
"
$username= 'lixo';
$username = 'lixo';
exec('su - vpopmail -c
"/var/qmail/bin/maildirmake/home/vpopmail/domains/wwlib.lan/" . $username');
"
But I get the error:
"/var/qmail/bin/maildirmake/home/vpopmail/domains/wwlib.lan/: Not a
directory"
Which means that the $username variable isn't being appended to the string.
Any help would be appreciated.
Warm Regards,
Mário Gamito
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