Herman Gomez wrote:
Hi,
Here is something I used to do in C/C++ to include/exclude automaticaly
all debugging code at compiling time:
#define debug TRUE
#ifdef(debug)
//debugging code
#endif
That way I can include/exclude easily all debugging code in the final
compiled code. In PHP I have not been able to find anything like that.
The only solution I've found is having this kind of code in every debug
code block:
if ($debug) {
//debugging code
}
But this means that the debugging code is in the final compiled
(interpreted) code, wasting cpu cycles even if there won't be any
debugging in production.
Does somebody know if there is something like conditional compilation in
PHP that I can use?
Regards,
Herman Gomez
Madrid, Spain.
Well PHP isn't compiled it's interpreted. Still I don't see much diff
and no overhead between the following:
#ifdef(debug)
//debugging code
#endif
---and---
if (defined('DEBUG')) {
//debugging code
}
I don't think checking a define is cpu intensive or even measurable.
You could "assume" that it's defined as true or false and:
if (DEBUG === true)) {
//debugging code
}
Still, I don't think that even checking $debug is measurable.
-Shawn
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