date('l', mktime(0,0,0, $Month, $Day, $Year));
----- Original Message -----
From: "Tyler Longren" <[EMAIL PROTECTED]>
To: "php-general" <[EMAIL PROTECTED]>
Sent: 2001. június 25. 16:58
Subject: [PHP] date -> day
> Hello,
>
> I have something like this:
> $Month = "6";
> $Year = "2001";
> $Date = "1";
>
> Is there any relatively simple way to get the day out of that? For example,
> the day for 6-1-2001 would be Friday.
>
> Thanks,
> Tyler
>
>
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