Rather than trying to break it into an array, you can examine the rightmost
character as follows
$search="dogs";
if(substr($search,-1)=='s') $search=substr($search,0,-1);
This checks if the last character is an s and if it is then set search to
the same string but without the s.. note, does not handle multiple word
queries.. for this you would need to break the string into words (something
you would probably have to do anyway) and do this for each of those...
For more info on substr seet http://php.net/substr
----- Original Message -----
From: "AJDIN BRANDIC" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Tuesday, July 03, 2001 11:10 AM
Subject: [PHP] search
> Hi all
>
> I've got search facility (php-mysql) which is very simple. If i search
> for 'dog' it will find any records containing words 'dog' or 'dogs' or
> 'dogowner' etc. But if I search for 'dogs', words 'dog' and 'dogowner'
> will not be found. This is a classic case so there must be a solution to
> it but I cannot find one. I tried to do something like
> if word is 'dogs' then I do the search,
> then break word 'dogs' into an array and check if the last element is an
> 's'. If it is remove it, reconstrust the string,which will give 'dog',
> and do search for that too.
> Then display results. Well I connot find a way of breaking a string into
> an array. How do I break 'mynameis' into an array of 8 elements?
> This has got loopholes but still it is better than what I have now.
>
> Thanks
>
> Ajdin
>
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