On Tue, 2009-06-23 at 15:07 -0400, Eddie Drapkin wrote:
> It's just foreach($foo as $key => &$item) { }
>
> You can't assign the key by reference >.>
>
> On Tue, Jun 23, 2009 at 3:04 PM, Ashley
> Sheridan<a...@ashleysheridan.co.uk> wrote:
> > On Tue, 2009-06-23 at 12:56 -0600, kirk.john...@zootweb.com wrote:
> >> Andres Gonzalez <and...@packetstorm.com> wrote on 06/23/2009 12:26:38 PM:
> >>
> >> > I want to modify $results within the foreach. In other words,
> >> > during a given pass of this iteration, I want to delete some
> >> > of the items based on particular conditions. Then on the next
> >> > pass thru the foreach, I want $results to be the newer, modified
> >> > array.
> >> >
> >> > This does not seem to work. It appears that the foreach statement
> >> > is implemented such that $results is read into memory at the start
> >> > so that any modifications I make to it during a given pass, are ignored
> >> > on the next pass. Is this true?
> >>
> >> foreach works on a copy of an array, so the behavior you saw is expected.
> >> See the online manual.
> >>
> >> You could use a while loop, or, instead of unset-ing elements of $results,
> >> store the elements you want to keep into a new array.
> >>
> >> Kirk
> >
> > What about passing it by reference?
> >
> > foreach($results as &$key => &$item)
> > {
> > // modify items here
> > }
> >
> > Thanks
> > Ash
> > www.ashleysheridan.co.uk
> >
> >
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> > PHP General Mailing List (http://www.php.net/)
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> >
> >
Yeah, hehe, I was trying to remember off the top of my head, and
obviously forgot! :p
*slaps self*
Thanks
Ash
www.ashleysheridan.co.uk
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