"Daevid Vincent" wrote:
>
>
>> -----Original Message-----
>> From: Ben Dunlap [mailto:[email protected]]
>> Sent: Friday, October 02, 2009 2:58 PM
>> To: [email protected]; Daevid Vincent
>> Subject: Re: [PHP] Whacky increment/assignment logic with
>> $foo++ vs ++$foo
>>
>> > mind-blowing. What the heck /is/ supposed to happen when
>> you do this:
>> >
>> > $a = 2;
>> > $a = $a++;
>> > echo $a;
>> >
>> > Seems like any way you slice it the output should be 3. I
>> guess what's
>>
>> ... and, in fact, that /is/ how C behaves. The following code:
>>
>> int a = 2;
>> a = a++;
>> printf("a = [%d]\n", a);
>>
>> Will output "a = [3]". At least on Ubuntu 9 using gcc 4.3.3.
>>
>> So I retract my initial terse reply and apologize for misunderstanding
>> your question.
>>
>> Ben
>
> EXACTLY! :)
>
> God (or diety of your choice) bless you for "getting" what I'm saying and
> proving that it's not "C" like either. That just adds credence to my/our
> argument.
>
>
> d
Well, Daevid,
I still do appreciate the difference between
$a = 1;
$b = $a++;
// $b should be 1
and
$a = $a++;
$b = $a;
// $b should be 2
unless PHP manages to exhibit some overlay problem (read: bug) for $a in
the 2nd case.
True?
joost.
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