Hi, Yes, what Ashley said is correct. Also, if you want to avoid writing $perm several times in the if, or if you have a lot of permissions you can do:
if (in_array($perm, array(11, 22))) And you can put in that array all the permissions you need to. Regards, Jonathan On Fri, Dec 18, 2009 at 3:47 PM, Ashley Sheridan <a...@ashleysheridan.co.uk> wrote: > On Fri, 2009-12-18 at 10:21 -0800, Allen McCabe wrote: > >> In a nutshell: >> >> Will this work? >> >> if ($perm == (11 || 12)) >> >> >> Explanation: >> >> I am laying the groundwork for a photo viewing system with a private and >> public mode, and additionally if an admin is logged in, there is an >> additional level of permission. I came up with a number system to make it >> easier (and is calcualted by a class) so now, instead of checking against >> the $mode variable, if the user is logged in, and then what their user level >> is if they are logged in, I just check against some numbers (the class >> evaluates all those conditions and assigns the appropriate number a single >> permission variable, $perm. > > > That equates to if($perm == true) as 11 in this case translates to true > (being a positive integer) The code never needs to figure out the || > part, as the first part is true. > > I think what you'd want to do is possibly: > > if($perm == 11 || $perm == 12) > > Thanks, > Ash > http://www.ashleysheridan.co.uk > > > -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
