On Sun, 2010-06-13 at 18:35 -0400, Rick Dwyer wrote:
> OK, I get the following error:
>
> Warning: basename() expects parameter 1 to be string, array given in....
>
> When I use the following:
>
> $thepath = parse_url($url);
> $filename = basename($thepath);
>
> Is my variable thepath not automatically string?
>
> --Rick
>
>
> On Jun 13, 2010, at 6:23 PM, Ashley Sheridan wrote:
>
> > On Sun, 2010-06-13 at 18:13 -0400, Rick Dwyer wrote:
> >>
> >> Hello List.
> >>
> >> I need to parse the PATH portion of URL. I have assigned the path
> >> portion to a variable using the following:
> >>
> >> $thepath = parse_url($url);
> >>
> >>
> >> Now I need to break each portion of the path down into its own
> >> variable. The problem is, the path can vary considerably as follows:
> >>
> >> /mydirectory/mysubdirectory/anothersubdirectory/mypage.php
> >>
> >> vs.
> >>
> >> /mydirectory/mypage.php
> >>
> >> How do I get the either of the above url paths broken out so the
> >> variables equal the following
> >>
> >> $dir1 = mydirectory
> >> $dir2 = mysubdirectory
> >> $dir3 = anothersubdirectory
> >> $page = mypage.php
> >>
> >> ...etc... if there were 5 more subdirectories... they would be
> >> dynamically assigned to a variable.
> >>
> >> Thanks for any help.
> >>
> >> --Rick
> >>
> >>
> >>
> >
> > $filename = basename($path);
> > $parts = explode('/', $path);
> > $directories = array_pop($parts);
> >
> > Now you have your directories in the $directories array and the
> > filename in $filename.
> >
> > Thanks,
> > Ash
> > http://www.ashleysheridan.co.uk
> >
> >
>
>
Because you've given it an array. Your original question never mentioned
you were using parse_url() on the original array string. parse_url()
breaks the string into its component parts, much like my explode
example.
Thanks,
Ash
http://www.ashleysheridan.co.uk
