Re: [PHP] Re: Simplest way of enforcing an array of instances of a specific class but treating the whole thing as an array.

[David Harkness]

If each array will contain a single type of object, but you need many of
these arrays, each containing a different type of object, I recommend
creating a generic "instances-of-class" array using ArrayObject. You can
enforce the type in append(), offsetSet(), and exchangeArray() and then
check the configured type in methods that want to enforce it.

    function drawMap(TypedArray $latLngs=null) {
        if ($latLngs && !$latLngs.containsOnly('LatLng')) {
            throw new InvalidArgumentException('$latLngs must contain only
LatLngs');
        }
        ...
    }

I guess since there are only three methods to override it wouldn't be too
painful to create a separate class for each type to get method declaration
type hinting. If you aren't containing too many classes and you pass them
around a lot, it may be worth it since you won't have to test the container
inside the method at all.

    function drawMap(LatLngArray $latLngs=null) ...

Looks like someone beat us to it:

    http://liamgraham.wordpress.com/2007/05/21/typesafe-arrays-for-php/

David