[PHP] PHP- something tha i don't understand

[Yassel Omar Izquierdo Souchay]

Hi again
Here is the part of before code

8:$result = mysql_db_query("users", $query); 
9:$r=mysql_fetch_array($result); 
10: $count=$r["count"];

And the error message is 
Warning: Supplied argument is not a valid MySQL result resource in 
c:\inetpub\wwwroot\PhpAndMysqlTest\test2\reg1.php3 on line 9


If somebody see something abnormal please let me know.

Thanks 
Yassel